Hi everyone,
Can someone please explain how to calculate the below? Specificially the probability of radios? Thanks
A parking lot has 100 red and blue cars in it.
- 40% of the cars are red.
- 70% of the red cars have radios.
- 80% of the blue cars have radios.
What is the probability of selecting a car at random that is either red or has a radio?
Moosey
#2
P(red or radio) = P(red)+P(radio)-P(red and radio)
P(red): 0.4 given
P(radio): total probability of blue or red with radio: 0.4*0.7+0.6*0.8=0.76
P(red and radio): 0.4*0.7=0.28
answer is: 0.4+0.76-0.28=0.88
Is this the answer?
(to be honest I’m so tired I can’t solve simple things…)
Here’s another way of getting to the same answer. It’s a bit longer than Moosey’s approach, but it also works:
P(red or radio) = P(red) + P(blue and radio)
= P(red) + P(blue)xP(radio|blue) = 0.40 + 0.60(0.80) = 0.88
And another way:
P(red or radio) = 1 – P(blue and no radio)
= 1 – P(blue)P(no radio | blue)
= 1 – (0.6)(0.2)
= 1 – 0.12
= 0.88