There are a few instances in the curriculum where you need to solve for x in an equation such as this : 500=32x + 25(1-x). I have just been solving through interation , but I would like a faster way. Can someone she some light on a faster way to solve for x or rearrange the equation?
I never took proper math in high school so I learned this way too late in life.
Multiply the 25 by both terms in the bracket, then you have 25 - 25X, then move the 25 onto the other side so all #'s are on 1 side and all #X are on the other side, then divide both by #X and you got what your X is equal to.
Hmm. Thank you, but I guess I’m a little slow. Not really following your explanation. Could you show your work?
500 = 32_x_ + 25(1 − x)
500 = 32_x_ + 25 – 25_x_
475 = 7_x_
x = 475 / 7 ≈ 67.85
Iteration for an equation that is linear in x??? Huh? Wha?
I propose MC method :).
If the larger term is x, and the smaller term is (x_-1_), you can simplify the steps.
Just take the target term (500) and minus the smaller term (25) = 475
Take the larger term (32) and minus the smaller term (25) = 7x
The rest is the same:
475 = 7x
_x = 475 / 7 = 67.9 _
Thank you magician and djdevz. Much appreciated!
You’re welcome.