Can somebody please explain the answer - I thought because the test statistic 2.016733 > critical value 1.96 means the null is rejected, and that there is no heteroskedacity
Clarification appreciated - cheers!
Hi, I’m not doing mocks yet, but for heteroskedacity you have to use the Chi square test not the t test
It’s because you hypothesis is unconditional Hererokedasticity, soy you don’t want to reject it… as the t statistic was higher, you reject the null hypothesis and accept condicional heteroskedasticity