Delta measures the slope Gamma measures the curvature
Correct Also, Delta measures change in call price to the change in underling. Gamme measures change in delta to the change in underling.
You can relate delta and gamma to two different theories Theory 1: Delta = 1st derivative Gamma = 2nd derivative Theory 2: Delta = duration Gamma = convexity
A practical way to think about this is that the delta gives you the instantaneous hedge ratio, and Gamma tells you how badly things can go wrong with static hedging.
Delta close to 1 when call option deep in the money delta close to -1 when put option deep in the money. Delta close to zero when option ( call or put ) just at the the money. Hedge ( delta hedge ) most effective when Delta close to zero . So Gamma is highest when option ( call or put) is just at the money, and lowest ( close to zero) when the option is deep in the money
There was one Schweser EOC question that always got me. It was something along the lines of: “A put option with exercise price of $40 is at-the-money. If the stock suddenly fell $10.00, delta and gamma would: a. Both increase b. Both decrease c. One would increase and one would decrease” Correct answer: B Gamma would obviously decrease, but what always got me was as the delta of a put moves from -.25 to say -.50, it is actually decreasing. I got mixed up by thinking of delta in absolute value terms.
Good thread…
job that’s a great q gamma decreases b/c … at the money = highest gamma delta would move closer to -1, which is a decrease so they both decrease
So if it was a call option and the price rose suddenly , one would rise ( delta) and one would fall ( gamma)
janakisri Wrote: ------------------------------------------------------- > So if it was a call option and the price rose > suddenly , one would rise ( delta) and one would > fall ( gamma) Yes