# Don't remember seeing this

Was this in the book? What is up with the denominator in the answer. If it is r*2 then you would have a negative number which you can’t take the square root of. A study of 40 men finds that their job satisfaction and marital satisfaction scores have a correlation coefficient of 0.52. At 5% level of significance, is the correlation coefficient significantly different from 0? A) No, t = 1.68. B) Yes, t = 3.76. C) No, t = 2.02. Your answer: A was incorrect. The correct answer was B) Yes, t = 3.76. H0: r = 0 vs. Ha: r ≠ 0 t = [r √(n – 2)] / √(1 – r2) tc (α = 0.05 and degrees of freedom = 38) = 2.021 t > tc hence we reject H0.

the denominator is = (1-r2)^1/2 for some reason the square root sign did not come through. 1-.52^2 = .7296^1/2 = .854

Formula didnt transfer correctly it should be: t = [r * (n-2)^(1/2)] / [(1-r2)^(1/2)]

Ok so it is r^2 and not r2? That would make more sense. However I still dont remember seeing this. Was it in the curriculum?

Oh yeah.

test of significance of the correlation coefficient real early on in Quant, first few pages really irrc