How would there be heteroskedasticity when the t-test is greater thant the critical value?

Exhibit 5.

EXHIBIT 5

UNIT ROOT TEST FOR NONSTATIONARITY AND THE TEST FOR HETEROSKEDASTICITY

Unit root test statistic −18.7402 Unit root test critical value at the 5% level of significance −2.89 Heteroskedasticity test statistic 2.016733 Heteroskedasticity test critical value at the 5% level of significance 1.96

Q. Based on the results reported in Exhibit 5, the AR(1) model is best described as having:

Your null hypothesis test is H_{0}: no Heteroskedactisty so with your t value oof 2.016 which is higher than the 1.96 critical value you got a significant test here and reject that there is no Heterskedacitisty and conclude its existence.