+1
MrSmart: iamMichael: MrSmart: iamMichael: MrSmart:Logically, first time takers should have the least chance of passing.
Too many assumptions in this statement with no support.
random sample, which would you bet on, 1st or 10th?
No idea what you mean?
If I had a group of random L3 candidates. Let’s say 1,000 people, completley random, different countries, age, jobs…etc
One group sitting for their first time, the other group sitting for their second time. Who would you bet on having the higher pass rate overall?
I would bet they would be very similar. First timers, as a whole, are likely a smarter group…but retakers are a more experienced group. Each have an advantage over the other that I cannot quantify. I would guess the performance of the two groups to be close to even.
This is where you’re wrong, assuming first time sitters are smarter when they could have well been sitting L3 after 5 time retakes for L2.
Don’t forget I said a “random sample” for a reason, it controls for ONLY the attempts, everything else is assumed to be statistically equal over an infinitley large sample.
I would take someone sitting for the second, or the 100th time than someone on their first time. Experience is simply on their side, and a large sample offsets any other advatnages, or disadvantages that may arise by conjecture.
Topperharley: MrSmart: iamMichael: MrSmart: iamMichael: MrSmart:Logically, first time takers should have the least chance of passing.
Too many assumptions in this statement with no support.
random sample, which would you bet on, 1st or 10th?
No idea what you mean?
If I had a group of random L3 candidates. Let’s say 1,000 people, completley random, different countries, age, jobs…etc
One group sitting for their first time, the other group sitting for their second time. Who would you bet on having the higher pass rate overall?
I would bet they would be very similar. First timers, as a whole, are likely a smarter group…but retakers are a more experienced group. Each have an advantage over the other that I cannot quantify. I would guess the performance of the two groups to be close to even.
This is where you’re wrong, assuming first time sitters are smarter when they could have well been sitting L3 after 5 time retakes for L2.
Don’t forget I said a “random sample” for a reason, it controls for ONLY the attempts, everything else is assumed to be statistically equal over an infinitley large sample.
I would take someone sitting for the second, or the 100th time than someone on their first time. Experience is simply on their side, and a large sample offsets any other advatnages, or disadvantages that may arise by conjecture.
Makes no sense. What?
This thread needs to die
^^ id bet on someone on their second attempt over a random 1st timer ( but not someone going for the 3rd/4th time…)
MrSmart: Topperharley: MrSmart: iamMichael: MrSmart: iamMichael: MrSmart:Logically, first time takers should have the least chance of passing.
Too many assumptions in this statement with no support.
random sample, which would you bet on, 1st or 10th?
No idea what you mean?
If I had a group of random L3 candidates. Let’s say 1,000 people, completley random, different countries, age, jobs…etc
One group sitting for their first time, the other group sitting for their second time. Who would you bet on having the higher pass rate overall?
I would bet they would be very similar. First timers, as a whole, are likely a smarter group…but retakers are a more experienced group. Each have an advantage over the other that I cannot quantify. I would guess the performance of the two groups to be close to even.
This is where you’re wrong, assuming first time sitters are smarter when they could have well been sitting L3 after 5 time retakes for L2.
Don’t forget I said a “random sample” for a reason, it controls for ONLY the attempts, everything else is assumed to be statistically equal over an infinitley large sample.
I would take someone sitting for the second, or the 100th time than someone on their first time. Experience is simply on their side, and a large sample offsets any other advatnages, or disadvantages that may arise by conjecture.
Makes no sense. What?
Try re-reading.