I tried searching, I know this is probably straightforward, but I cant work out how to do this. Can anybody shine a light on it?

Take equation Qg gas=138,500-12,500p gas

Inverted = 11.08-0.00008Qd gas

I tried searching, I know this is probably straightforward, but I cant work out how to do this. Can anybody shine a light on it?

Take equation Qg gas=138,500-12,500p gas

Inverted = 11.08-0.00008Qd gas

First year algebra, my friend:

Qg =138,500 − 12,500Pg

Subtract 138,500 from both sides:

Qg − 138,500 = −12,500Pg

Divide both sides by −12,500:

(Qg/−12,500) – (138,500/−12,500) = Pg

−0.00008Qg + 11.08 = Pg

Thnaks I’m still stuggling with this bit, Iknow it should be easy, how do I get the value to insert in **Qg?**

Here’s another one I’m looking at?

800-4p

I understand this step -800=-4p

When I get to here -0.25+200= P I dont understand where the -0.25 comes from?

Q = 800 - 4P was the equation?

Q - 800 = - 4P

Q(1/4) - 800/4 = - P

0.25Q - 200 = - P

-0.25Q + 200 = P

You really need help on algebra

Adam:

I agree with Harrogath: if you’re having trouble with this, you need a refresher on algebra.

Hie thee to a bookstore . . . well, those barely exist these days, so hie thee to Amazon . . . and get a copy of Algebra for Dummies.

It’ll serve you well.

Look for youtube videos that explain Algebra and Linear equations. That will also help.

Cheers guys.