The same as a continuously compounded rate? Thanks in advance.
I don’t think so. The continuous compounding one uses function “e” in the calculator. It is assumed to be compounding lot more frequently than the constant rate and as a result gives you more in result than the constant rate.
Ashwin Wrote: ------------------------------------------------------- > I don’t think so. The continuous compounding one > uses function “e” in the calculator. It is assumed > to be compounding lot more frequently than the > constant rate and as a result gives you more in > result than the constant rate. That is what I thought. Finquiz used the term constant interest rate and then calculated it as e.