Schwester Book 5 Pg 66 Binomial Options Arbitrage

Hi Guys,

I was reading the example problem they gave, and I will try to summarize it here:

Stock Price today is $30

Probability of an up move to $40 is 55%

Probability of a down move to $22.25 is 45%

There is a call option for $30 in 1 year selling for (mispriced) $6.50. Book asks how we can arbitrage this.

The book says:

  1. Short 100 call options @ $6.50 per call

  2. They calculate the “delta” (for hedging) as (10-0)/(40-22.50) = .5714 shares per option, so purchase 57.14 shares

  3. “A portfolio that is long 57.14 shares of stock at $30 per share and short 100 calls at $6.50 per call has a net cost of:”

Net portfolio cost = (57.14 * $30) - (100 x $6.50) = $1,064

  1. The book then states: “The values of this portfolio at maturity if the stock moves up to $40 or down to $22.50 are:”

portfolio value in up-move = (57.4 x $40 ) - (100 x $10) = $1,286

portfolio value in down-move = (57.4 x $22.50) - (100 x $0) = $1,286

In the up scenario, if you short a call option, the person on the other side has the right to buy at $30, correct? So they would exercise the option and you would have to deliver 100 shares of stock at $30. You only own 57.14 shares, where are they getting the other shares? How are we only losing $1,000 (100 x $10) to the short call options in this case?

Any help is appreciated. I might be missing something blatant.

Thanks

Bump - anyone? S2000 Magician?

It’s also the price of the option. If it had equalled the price we get by arbitrage pricing, we wouldn’t have shorted. The arbitrage price should be at a price lower than $6.50. Since this is overpriced we short the call option in such a way that we can get a positive payoff at the end of 1 year. As more and more traders see this oppotunity, they will ultimately bid the price down.

Also, the return we get by this combination is more than 20%. But if the option traded at a price calculated by the arbitrage model, we would have earned the Risk-free rate.

Hi Parth,

I understand that the price of this call option presents us with an arbitrage opportunity, but I don’t understand how when we are holding 57.14 shares of the underlying stock, and the person has the right to purchase 100 shares @ $30 from us (because of the option) that we don’t lose more money.

In my mind, if the stock goes to $40, our portfolio would be: 57.14* 40 = $2285.6 The person has the right to BUY 100 shares from us @ $30, so we would have to get another 42.86 shares in the open market @ 40, which costs us $1714.4

So we’ve gained $571.4 from owning 57.14 shares from $30 to $40, and $650 from selling the option. BUT, then we have to deliver an additional 42.86 shares @ 30, which will cost us $1285.8.

Stock Gain ($571.4) + Option Gain ($650) - Delivering 42.86 shares @ 30 ($1714.4) = -$493

I feel like I am missing something here.

The way i see it:

It is assumed that options settle in cash so the underlying is never delivered. Only the amount of loss for the call writer will be deducted from his account i.e. S+ = $40 At initiation, portfolio value = $1,064

So, after an up-move our loss is 100 x $10 but an overall profit of 57.14 x $40 (2286 - 1000) = $1,286. Assuming a down move, an option holder will not exercise his/her option at contract expiration. We have already collected the premium of 100x$6.50 so now ( after 1 year ) the portfolio value is 57.14 x $22.50 = $1,286