An analyst gathered the following information about a common stock: Probabilit…Possible Rate of Return 0.35…8% 0.3…10% 0.25…15% 0.1…20% The expected return and expected standard deviation of returns, respectively, for the common stock are closest to: A. 12% and 3.9%. B. 12% and 15.3%. C. 14% and 3.9%. D. 14% and 15.3%. Answer is A…I got 12%…not getting 3.9%
If it helps any, so you don’t have to do that long equation the sq. root of 15.3 = 3.9%
[.35*(8%-12%)^2+.3*(10%-12%)^2+.25*(15%-12%)^2+.1*(20%-12%)^2]^(1/2)=3.9306
Now that’s a trick I must learn!
I get 11.55 and 3.9046 Are you solving for variance and not stddev? Are you squaring the deviation from the mean before weighting the value?
-_- forward looking std dev = (sum(i=1…n) where Pi(Xi-Xbar)^2)^.5 you should get the answer. in other words, [.35(8-12)^2+.3(10-12)^2+.25(15-12)^2+.1(20-12)^2]^.5=3.93065
Expected Stand Deviation - x- 5% Y-4% Cov = .75 Weights x 60% Y 40% What is expected standard devation of port - Variance =( .6^2 * 5^2 )+ (.4^2 * 4^2) + 2(.6)(.4)(5)(4)(.75) = (9) + (2.56) + (7.2) = 18.76 Standard Deviation = Sqrt(18.76) = 4.33 isnt the last part of formula - 2wwCOV (WHY IS Standard DEviation Used) in formula Above??
map, I will gladly find the shortcuts on the math if you will follow up and do the math on problems that don’t have shortcuts…for me! LOL
Expected Stand Deviation - x- 5% Y-4% Cov = .75 Weights x 60% Y 40% What is expected standard devation of port - Variance =( .6^2 * 5^2 )+ (.4^2 * 4^2) + 2(.6)(.4)(5)(4)(.75) = (9) + (2.56) + (7.2) = 18.76 Standard Deviation = Sqrt(18.76) = 4.33 isnt the last part of formula - 2wwCOV (WHY IS Standard DEviation Used) in formula Above??
shahravi123 Wrote: ------------------------------------------------------- > Expected Stand Deviation - > > x- 5% > Y-4% > > Cov = .75 > > Weights > > x 60% > Y 40% > > What is expected standard devation of port - > > Variance =( .6^2 * 5^2 )+ (.4^2 * 4^2) + > 2(.6)(.4)(5)(4)(.75) = (9) + (2.56) + (7.2) = > 18.76 > > Standard Deviation = Sqrt(18.76) = 4.33 > > isnt the last part of formula - 2wwCOV (WHY IS > Standard DEviation Used) in formula Above?? You’re answering the wrong question. Standard deviation, not covariance.
You’re bag is full of tricks:) I’ve seen!
this is standard deviation of a two stock portfolio. first question is about expectations of one stock the second is the computing expected std dev of two stocks held in one portfolio. (hence portfolio management)
yes but variance of port is - w1^2* Variance1 + W2^2* Varinace +2*w1 *w2*COV
the first question is not a portfolio… its one stock.
shahravi123 Wrote: ------------------------------------------------------- > Expected Stand Deviation - > > x- 5% > Y-4% > > Cov = .75 > > Weights > > x 60% > Y 40% > > What is expected standard devation of port - > > Variance =( .6^2 * 5^2 )+ (.4^2 * 4^2) + > 2(.6)(.4)(5)(4)(.75) = (9) + (2.56) + (7.2) = > 18.76 > > Standard Deviation = Sqrt(18.76) = 4.33 > > isnt the last part of formula - 2wwCOV (WHY IS > Standard DEviation Used) in formula Above?? 1) Why is this post written like a ransom note? 2) I think there is a typo there and the 0.75 is supposed to be a correlation not a covariance.