Consider a sample of 32 observations on variables X and Y in which the correlation is 0.30. If the level of significance is 5%, we: A) conclude that there is significant correlation between X and Y. B) cannot test the significance of the correlation with this information. C) conclude that there is no significant correlation between X and Y. Your answer: C was correct! The calculated t = (0.30 × √30) / √(1 − 0.09) = 1.72251 and the critical t values are ± 2.042. Therefore, we fail to reject the null hypothesis of no correlation. ------------ what is the formula for tstat calculation here?

edited: The calculated t = (0.30 × (sqrt30)) / sqrt(1 − 0.09) = 1.72251

dammit The calculated t = (0.30 × (sqrt30)) / sqrt(1 - 0.09) = 1.72251

t= r*sqrt(n-2) divided by sqrt (1-r(square))

where is the LOS for this? i thought tstat was = estimate - actual / estimate’s S.E

pacmandefense Wrote: ------------------------------------------------------- > where is the LOS for this? i thought tstat was = > estimate - actual / estimate’s S.E that is for the test of a regression coefficient they are looking for the test of the correlation coefficient

see quick sheet, 2nd formula! what about my question? do i always have to look at the absolute value of the critical value from the t-table, even in a two-sided test?

sorry. went to sleep. yes