**A parking lot has 100 red and blue cars in it.**

**40% of the cars are red.****70% of the red cars have radios.****80% of the blue cars have radios.**

**What is the probability of selecting a car at random that is either red or has a radio?**

I calculated it as:

.40 + .70 - (.40 X .70) = .82

I got this wrong and here is the explanation:

**P(red or radio) = P(red) + P(radio) – P(red and radio) = 0.40 + 0.76 – 0.28 = 0.88 or 88%.**

Where did the .76 come from?