What was the answer for that questions .5 yes and .5 no and joint prob was .33. It should be independent, right?

It shouldn’t be independent, if independent P(AB)=p(A).P(B), so joint prob. is .25 I don’t remember the exact question…

Joint prob was 1 to 3 or .25, but I marked independent for that too. T/G

0.5 + 0.5 - 0.33 = 0.67? p(A) + p(B) - P(AB) = p(A or B) that was it asking right?

In they were independent, they would have to satisfy the following condition: p(A or B) = p(A) x p(B) - p(A and B), where p(A and B) is p(A) x p(B) Since 0.5x0.5 is not equal to 0.33, these event are not independent. The increase in probability of A and B happening is due to A and B being somewhat related.

so they are “related events” right?

1 to 3 IS NOT .333 it is .25 .5*.5=.25 Therefore the events are independent. answer was .25 and independent.

what test was test number was that on ?

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The test said the odds of the event occurring together is “1 to 3” (if I recall correctly), which is .25, making the events independent. If they said 1 IN 3, then the odds of the event occurring would be .333 and would they be related. “in” vs “to” does anyone recall for sure? T/G

LongOnCfa is correct.

1010 or 2020 or ???..

95% sure it was 1 to 3…i remember thinking “this is gonna trick a lot of people”

1010

It was. 100%.

i’m with LongOnCFA.

+1 for me. I owe you one LongonCFA

and -1 for me… but, I still cannot recall seeing 1 to 3. And, to make things worse, I had plenty of time to read everything carefully.

-1 for me too… I did not interpret 1 to 3 correctly.

LongOnCFA Wrote: ------------------------------------------------------- > 1 to 3 > > IS NOT .333 it is .25 > > .5*.5=.25 > > Therefore the events are independent. > > answer was .25 and independent. that’s how I reasoned it out as well. Thanks, LongOnCFA. Got scared there for a sec, I already found a bunch of mistakes, didnt want this to be another one. Dubs, it was on 1010. odd # page, second Q from the bottom